Monday,+February+8,+2010Set+6

Assignment: p. 303 # 2, 3, 4, 6, 8, 11, 13

a = 60,000 2400000 = 60000 x b^2 40 = b^2 40^1/2 = (b^2)^1/2 6.325 = b
 * 2: Jonathan
 * a)** The points given are (0, 60,000) and (2, 2,400,000).
 * y = 60,000(6.325)^x**

y = 60000(10123) y = 607,380,000
 * b)** y = 60000(6.325)^5
 * 607,380,000 rabbits**

3.333e^-5 = 6.325^x log3.333e^-5 ÷ log6.325 = x -5.58 = x
 * c)** 2 = 60000(6.325)^x
 * The first pair of rabbits was introduced around 1860.**


 * d)** Their number increased exponentially, because each time they multiplied, a percentage of the total population was added to the existing population. Since the total population increased each year, the number they increase by is multiplied. Thus, you could say the rabbits multiply.

g=seconds out of gas s=speed in (km/h) (g,s) a.(0,64) (10,48) a=64
 * 3: James

48=64*b^10 b=.972

s=64*(.972)^g

b. s=64*(.972)^25 s=31.466

c.10=64*(.972)^g .15625=(.972)^g g=65.364

f(0) = 192 f(20)=48 a x b^x = y a x 1 = 192 a= 192 192 x b^20 = 48 b^20 = 1/4 b= (.25)^ 1/20
 * 4: Jeremy

20 degrees C = 48 hrs. 40 degrees C = 12 hrs. 60 degrees C = 3 hrs 80 degrees C = 3/4 hrs.

1000 = a*b^0 1052=1000*b^1 a=1000 b=1.052
 * 6: Gilad
 * a**. f(0)=1000 f(1)=1052
 * f(x)=1000*1.052^x

b.** 1000*1.052^10=Q 1000*1.660=Q Q=1660
 * By 10 years, there will be $1660

c.** 2000=1000*1.052^x 2=1.052^x log(2)=x*log(1.052) x=13.673
 * After 13.673 years, the savings account will total** **$2000**


 * 11: Cooper

a. Grade of 85 with two hours of studying b. 65, y-intercept c. sqrt(17)+2 or ~6.123 hours d.
 * 13: Charlie (wanted to post the equations directly using LaTeX, but could not convert the MathML...)